q is a charge out in space far from other charges. the points in space infinitel

Question

q is a charge out in space far from other charges. the points in space infinitely far from q are taken to be 0 reference for potential energy consider q1=1 microcoulomb and q2=-1 microcoulomb Skill Sheet Page 2 3cm 4 cm 0 is a charge out in space, far from other charges. The points in space infinitely far from Q are taken to be 0 reference for potential energy Consider qí = +l pC and q2 =-l pC How much work is required to bring a second charge gu from very far away to point Y or Z? What is the total potential energy of the 2 charges Q and qi when q is at Y or Z? If qi is released, what will be its kinetic energy when it gets very far away? gi is now gone. How much work is required to bring 92 from very far away to point Y or Z? What is the total potential energy of the 2 chargesQ and g2 when g2 is at Y or Z? If q2 was held very far from Q and then released, what What is the potential at points Y and Z? What is Vyz YZ How much work is required by an external force to move qu from Y to Z? How much work is required by an external force to move g2 from Y to Z? +1 pC

Explanation / Answer

There are many problem here or atleast 3 sets of problem.I will answer 1st set that is the 1st 3 questions in this.We are not allowed to answer multiple questions.

Part 1:
To bring charge to Y:
d = 4 cm =0.04 m
work done = potential energy at Y
= K*Q*q1/d
=(9*10^9)*(5*10^-6)*(1*10^-6) / (0.04)
= 1.125 J

To bring charge to Z:
d = sqrt(4^2+3^2) = 5 cm =0.05 m
work done = potential energy at Z
= K*Q*q1/d
=(9*10^9)*(5*10^-6)*(1*10^-6) / (0.05)
= 0.9 J

part 2:
Potential energy of 2 charges :
at Y:
potential energy at Y
= K*Q*q1/d
=(9*10^9)*(5*10^-6)*(1*10^-6) / (0.04)
= 1.125 J

at Z:
potential energy at Z
= K*Q*q1/d
=(9*10^9)*(5*10^-6)*(1*10^-6) / (0.05)
= 0.9 J

part 3:
Full potential energy will be converted to kinetic energy
for Y:
kinetic energy = 1.125 J

for Z:
kinetic energy = 0.9 J

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