my roof is 10 meters above ground and my cannon fires at an angle of 40 degrees

Question

my roof is 10 meters above ground and my cannon fires at an angle of 40 degrees above the horizontal with a speed of 25 m/s. what's the highest bird my cannon can hit. how far away horizontally will the highest bird be my roof is 10 meters above ground and my cannon fires at an angle of 40 degrees above the horizontal with a speed of 25 m/s. what's the highest bird my cannon can hit. how far away horizontally will the highest bird be my roof is 10 meters above ground and my cannon fires at an angle of 40 degrees above the horizontal with a speed of 25 m/s. what's the highest bird my cannon can hit. how far away horizontally will the highest bird be

Explanation / Answer

here

H = v^2 * sin(theta)^2 / 2 * g

H = 25^2 * sin(40deg)^2 / 2 * 9.8

H = 13.17 m

and the maximum height is 13.17 + 10 = 23.17 m

then by using the second equation of motion

y = vy * t + 0.5 * a*t^2

-10 = 25 * sin(40) * t + 0.5 * 9.8 * t^2

-10 = 16 *t - 4.9t^2

by solving this t = 3.8 sec

then the horizontal distance covered is

d = 25 * cos(40) * 3.8

d = 72.7 m

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