A block m 1 rests on a surface. A second block m 2 sits on top of the first bloc

Question

A block m1 rests on a surface. A second block m2 sits on top of the first block. A horizontal force

applied to the bottom block pulls both blocks at constant velocity. Here m1 = m2= m.

(a) What is the normal force exerted by the surface on the bottom block? (Use the following as necessary: m and g as necessary.)
N1 =

(b) What is the normal force exerted by the bottom block on m2? (Use the following as necessary: m and g as necessary.)
N2 =

(c) How would your answers to parts (a) and (b) change if m1 = 9m and m2 = m?

a) N1 = 10mg, N2 = mg

b) N1 = 10mg, N2 = 9mg

c) N1 = 4.5mg, N2 = 4.5mg

d) N1 = 8mg, N2 = 6.75mg

(d) How would your answers to parts a and b change if m1 = m and m2 = 9m?

a) N1 = 8mg, N2 = 6.75mg

b) N1 = 4.5mg, N2 = 4.5mg

c) N1 = 10mg, N2 = mg

d) N1 = 10mg, N2 = 9mg

Explanation / Answer

a) N1 = (m1 + m2)g = 2mg

B) N2 = m2g = mg

C) N1 =(m1 + m2)g = ( 9m + m) = 10mg

N2 = m2g = mg

ANs(A)

D) N1 = (m1 + m2)g = (m + 9m)g = 10mg

N2 = m2g = 9mg

Ans(D)

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