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Explain the trends in the magnitude of your errors for (a) the H atom and (b) th

ID: 1330361 • Letter: E

Question

Explain the trends in the magnitude of your errors for (a) the H atom and (b) the He^+ ion.

ocedures The tasks are preseeted in outline So 1. Use Equation 3.3 and cakulate the ive (5) lowest enengy levels for the hydrogen asom 2. Use the energes you cakulated in Step 1 to eakculate the energy and wwwelength of the photon emite as electroes in excited bydeogre atoms fall back to lower level There are a total of ten (10) transitions . Label eah of the transitkoos in the peevicnas Serp. Forph, the wwwkngth for the troeition fror frotn igh-5 to 2can be ien the label Assign the transit k as for the folkwingolNneA fr the lydner. .tem: Observed in am Probable Trawitk Probabie Transition 7.2 02.6 121.6 433.4 4861 12818 18781 000.0 Repeat Steps 1 through 3 for the Helon Assign the transitions for the following obserwA fr the Ile" kee in Probable Trassitce 25.6 30.4

Explanation / Answer

There are many questions here and I am allowed to answer only 1 at a time. So I will answer question number 1 for you.

En = - (2.178x10^-18 J)(z^2/n^2) <<<I think this is correct equation
for Hydrogen z=1
En = - (2.178x10^-18 J)(1/n^2)

for n=1,
E1 = - (2.178x10^-18 J)(1/1^2)
= - 2.178x10^-18 J

for n=2,
E2 = - (2.178x10^-18 J)(1/2^2)
= - 5.445x10^-19 J

for n=3,
E3 = - (2.178x10^-18 J)(1/3^2)
= - 2.42x10^-19 J

for n=4,
E4 = - (2.178x10^-18 J)(1/4^2)
= - 1.36125x10^-19 J

for n=5,
E5 = - (2.178x10^-18 J)(1/5^2)
= - 8.712x10^-20 J

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