A point charge + q is at the origin. A spherical Gaussian surface centered at th

Question

A point charge +q is at the origin. A spherical Gaussian surface centered at the origin encloses +q. So does a cubical surface centered at the origin and with edges parallel to the axes. Select "True" or "False" for each statement below.

Suppose (for this statement only), that q is moved from the origin but is still within both the surfaces. The flux through both surfaces remains unchanged.

If the radius of the spherical Gaussian Surface is varied, the flux through it also varies.

By symmetry, the E-Field at all points on the cubical surface is zero.

The area vector and the E-Field vector point in the same direction for all points on the cubical surface.

The Electric Flux through the spherical surface is the same as the Electric Flux through the cubical surface.

Explanation / Answer

All the questions are anwsered using Gauss Law , which states that - The total of the electric flux out of a closed surface is equal to the net charge enclosed divided by the permittivity.

1.) True. (Because Net charge enclosed still remains same.)
2.) False. (It doesn't depend on radius.)
3.) False. (Electric Field is not Zero)
4.) False. (Area vectors point outward from the surface. The electric field vector points directly away from the enclosed positive charge)
5.) True. (Because Net charge enclosed still remains same. in both the surface.)

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