A pivot is placed at Point L and a force of 40.0 N is directed downward perpendi

Question

A pivot is placed at Point L and a force of 40.0 N is directed downward perpendicular to the stick at Point J. One at a time, each of the following 3 forces are applied to the stick in the manner described. Where must these forces be applied in order to achieve static equilibrium? If the is no point that will work within reason, select the option None. A pivot is placed at Point G and a force of 20.0 N is directed downward perpendicular to the stick at Point D. What is the magnitude and direction of the force which must be applied at point E in order to obtain static equilibrium?
Upward ?
Downward ?

(A B C D E F G H J K L None) A force of 53.3 N directed upward perpendicular to the stick.
(A B C D E F G H J K L None) A force of 53.3 N directed downward perpendicular to the stick.
(A B C D E F G H J K L None) A force of 17.8 N directed upward perpendicular to the stick.

SO CONFUSED

Explanation / Answer

part 1:

let the force be F N,

it has to be directed downwards in order to balance the torque about the pivot

then F*distance GF=17*distance FH

==>F*3*16.4=17* 6*16.4

==>F=34 N, directed downwards

part 2:

the 3 forces mentioned are not supplied. hence can not be worked out.

part 3:

to balance the torque , the force has to be applied in upward direction

let force magnitude is F.

then F*distance GE=20*distance GD

==>F*8*16.4=20*5*16.4

==>F=12.5 N, directed upwards

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