a particle experiences a constant acceleration that is 30.5 degrees south west a

Question

a particle experiences a constant acceleration that is 30.5 degrees south west at 98.3 m/s^2. its initial velocity is 61.1 m/s east. what will be the particles speed after 10 seconds? a particle experiences a constant acceleration that is 30.5 degrees south west at 98.3 m/s^2. its initial velocity is 61.1 m/s east. what will be the particles speed after 10 seconds? a particle experiences a constant acceleration that is 30.5 degrees south west at 98.3 m/s^2. its initial velocity is 61.1 m/s east. what will be the particles speed after 10 seconds?

Explanation / Answer

here,

take north be the + y axis and east be the +x axis

speed of the particle , u = 61.1 m/s i

accelration of the particle , a = 98.3 m/s^2 ( - cos(30.5 ) i - sin(30.5) j)

a = - 84.7 i ms/^2 - 49.89 j m/s^2

time interval , t = 10 s

using first equation of motion

particles speed , v = ((u - ax*t ) , (0 - ay *t))

v = ((61.1 - 84.7*10 ) , (0 - 49.89 *10))

v = (- 785.9 i m/s - 498.9 j m/s)

the speed of particle , v = sqrt(785.9^2 + 498.9^2)

v = 930.88 m/s

the speed of the particle is 930.88 m/s

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