two children pulling a 11.2-kg sled along the snow. The first child exerts a for

Question

two children pulling a 11.2-kg sled along the snow. The first child exerts a force of F1 = 14 N at an angle 1 = 45° counterclockwise from the positive x direction. The second child exerts a force of F2 = 6 N at an angle2 = 30° clockwise from the positive x direction.

(a) Find the magnitude and direction of the friction force acting on the sled if it moves with constant velocity.

(b) What is the coefficient of kinetic friction between the sled and the ground

(c) What is the magnitude of the acceleration of the sled if F1 is doubled and F2 is halved in magnitude?

Explanation / Answer

a)
Net force on the sled on x axis = F1cos45 + F2cos30

Since velocity is constant, acceleration will be zero.

Since a is 0, the force is also zero.

Since net force is 0, the friction force will be equal to F1cos45 + F2cos30

b)
Ff = mu*m*g

mu * (mg + F2sin30 - F1Sin45) = F1cos45 + F2cos30

mu = F1cos45 + F2cos30 / (mg + F2sin30 - F1Sin45)

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