QUESTION Which of the original resistors dissipates energy at the greatest rate?

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QUESTION Which of the original resistors dissipates energy at the greatest rate? the 8.0 resistorthe 4.0 resistor    the 6.0 resistorthe 3.0 resistor EXERCISEHINTS:  GETTING STARTED  |  I'M STUCK! Suppose the series resistors in the example are now 4.00 and 2.00 while the parallel resistors are 4.00 (top) and 2.00 (bottom), and the battery provides an emf of 31.0 V. (a) Find the equivalent resistance. Req =  

(b) Find the currents I, I1, and I2. I = A I1 = A I2 = A QUESTION Which of the original resistors dissipates energy at the greatest rate? the 8.0 resistorthe 4.0 resistor    the 6.0 resistorthe 3.0 resistor QUESTION Which of the original resistors dissipates energy at the greatest rate? the 8.0 resistorthe 4.0 resistor    the 6.0 resistorthe 3.0 resistor the 8.0 resistorthe 4.0 resistor    the 6.0 resistorthe 3.0 resistor EXERCISEHINTS:  GETTING STARTED  |  I'M STUCK! Suppose the series resistors in the example are now 4.00 and 2.00 while the parallel resistors are 4.00 (top) and 2.00 (bottom), and the battery provides an emf of 31.0 V. (a) Find the equivalent resistance. Req =  

(b) Find the currents I, I1, and I2. I = A I1 = A I2 = A EXERCISEHINTS:  GETTING STARTED  |  I'M STUCK! Suppose the series resistors in the example are now 4.00 and 2.00 while the parallel resistors are 4.00 (top) and 2.00 (bottom), and the battery provides an emf of 31.0 V. (a) Find the equivalent resistance. Req =  

(b) Find the currents I, I1, and I2. I = A I1 = A I2 = A (a) Find the equivalent resistance. Req =  

(b) Find the currents I, I1, and I2. I = A I1 = A I2 = A Req I, I1, and I2. I I1 I2 I = A I1 = A I2 = A

Explanation / Answer

a)P=V^2/R

so power is inversly propotional to resistance

so lowest the resistor value more th epower dissipiation

so 3 ohm resistor will have more power dissipiation

4 and 2 are in parllel so

1/R=1/4+1/2

R=1.33 ohm

this in series with 4 ohm and 2ohm

so Req=1.33+4+2

=7.33 ohm

V=IR

31/7.33=I

4.22 amps=I

series ressitors have same current

so I1=4.22 amps

in parllel it will be divided so

V1=I1R1

=4.22*4

=8.22V

I=8.22/4

=2.05 amp

I=8.22/2

=4.11 amp

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