can you explain that to me ? Two uniformly charged rods (each with total charge

Question

can you explain that to me ? Two uniformly charged rods (each with total charge +12nC and length 10cm) are arranged as shown in the figure. One lies on the .v-axis and one lies on the y-axis. The electric field due to one rod is Erod=kQ/R(R-L) where k is the usual Coulomb force constant, R is the field point distance as measured from the far end of th rod, and Q is the charge on the rod. The field point P is at the origin, 5 cm from the end of each rod Calculate the linear charge density of one rod. Calculate the electric field magnitude due to one rod at the field point Calculate the total electric field due to both rods at the field point.

Explanation / Answer

a) linear charge densioty, lamda = Q/L

= 12 nc/0.1

= 120 nc/m or 0.12 micro C/m

b)

From the given data,

R = 5 + 10

= 15 cm

= 0.15 m

Erod = k*Q/(R*(R - L))

= 9*10^9*12*10^-9/(0.15*(0.15 - 0.1))

= 14400 N/c

c) Here electric field produced by both rods are perpendicular to each other.

so, Enet = sqrt(Erod^2 + Erod^2)

= sqrt(2)*Erod

= 1.414*14400

= 20364.7 N/c

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