Consider the two arrangements of batteries and bulbs shown in the figure below.

Question

Consider the two arrangements of batteries and bulbs shown in the figure below. The two bulbs are identical and have resistance R, and the two batteries are identical with output voltage V.†

(a) In case 1, with the two bulbs in series, compare the brightness of each bulb, the current in each bulb, and the power delivered to each bulb.

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(b) In case 2, with the two bulbs in parallel, compare the brightness of each bulb, the current in each bulb, and the power supplied to each bulb.

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(c) Which bulbs are brighter, those in case 1 or those in case 2?

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(d) In each case, if one bulb fails, will the other go out as well? If the other bulb doesn't fail, will it get brighter or stay the same?

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Explanation / Answer

A)

In case 1, the bulbs are in series then both the bulbs will glow with dim (with lesser brightness), the current is given by I= DeltaV/2R

and power is given by P =(DeltaV)2/2R

B)

In case 2 when two bulbs are in parallel then the rated voltage received by each bulb will be more, therefore they glow with more brightness, and current passing through the each bulb will

I =2(DeltaV)/R

and power is supplied to each bulb is P =2(DeltaV)2/R

C)

Case 2 in parallel it will glow with more bright because rated voltage will be received by each bulb will be more

D)

If in case 1 one bulb is failed then there will be no current flow through the other bulb. Where as in parallel in case 2 if one bulb is failed the other bulb glow with more brightness.

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