In the overhead view of the figure below, Jeeps P and 8 race along straight line

Question

In the overhead view of the figure below, Jeeps P and 8 race along straight lines, across flat terrain, and past stationary border guard A. Relative to the guard, Jeep 8 travels at a constant speed of 20.0 m/s, at the angle pi2 = 30.0 degree. Relative to the guard, Jeep P has accelerated from rest at a constant rate of 0.25 m/s2 at the angle pi1 = 55.0 degree At a certain time during the acceleration, Jeep P has a speed of 24.0 m/s. What is the velocity of Jeep B relative to Jeep B at that time What is the acceleration of Jeep P relative to Jeep B?

Explanation / Answer

a)

Vp = 24*cos55i + 24*sin55j

VB = 20*cos30i + 20*sin30j

vP - VB = (24*cos55 - 20*cos30) i + (24*sin55-20*sin30)j

Vp - VB = -3.55 i + 9.65 j m/s

magnitude = 10.2794

direction = tan^-1(-9.65/3.55) = 110

+++++

b)

aP = 0.25*cos55i + 0.25*sin55j

aB = 0

aP - aB = 0.25*cos55i + 0.25*sin55j

magnitude = 0.25

direction = tan^-1(sin55/cos55) = 55

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