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b) A dielectric in the shape of a thick-walled cylinder of outer radius R 1 = 4.

ID: 1333061 • Letter: B

Question

b) A dielectric in the shape of a thick-walled cylinder of outer radius R1 = 4.39 cm, inner radius R2 = 2.89 cm, thickness d = 1.75 mm, and dielectric constant ? = 1.91 is placed between the plates, coaxial with the plates, as shown in the figure. Calculate the capacitance of capacitor B, with this dielectric.

c) The dielectric cylinder is removed, and instead a solid disc of radius R1 made of the same dielectric is placed between the plates to form capacitor C, as shown in the figure. What is the new capacitance?

Top view Side view Capacitor A Metal disc 2 Capacitor B Air Dielectric Air Capacitor C 2 Dielectric

Explanation / Answer

a)

C = k _o A/d = 1 * 8.85e-12 * 3.1416*4.39e-2*4.39e-2/1.75e-3 = 3.06e-11 F

B)

C = C1 + C2

= k1e0A1/d + k2e0A2/d

= (1*8.85e-12*3.1416*0.0289*0.0289/1.75e-3) + (1.91*8.85e-12*3.1416*(0.0439*0.0439-0.0289*0.0289)/1.75e-3)

= 3.06 * 10^-11 F

C)

C1 = k1e0A1/(d/2) = 1*8.85e-12*3.1416*0.0439*0.0439/(1.75e-3/2) = 6.12e-11 F

C2 = k2e0A2/(d/2) = 1.91*8.85e-12*3.1416*0.0289*0.0289/(1.75e-3/2) = 4.0256e-11

C = C1C2/(C1+C2) = ( 1.9079e-11*4.0256e-11)/( 1.9079e-11+4.0256e-11)

==> C = 2.77 * 10^-11 F