I found the first part, please help with number 2 and 3 HCl consists of one H an

Question

I found the first part, please help with number 2 and 3

HCl consists of one H and Cl atom separated by 0.127 nm, the bond length. The Cl atom has a partial charge of -0.177e and the H atom has a partial charge of +0.177e, where e = 1.602x10-19 C is the electron charge.

What is the dipole moment of the molecule?

0.0359E-28 C*m

2)Now the HCl molecule is placed near a sodium ion Na+ with charge +1e. As shown in the figure, the distance between the Cl and Na atoms is d = 2.7 nm.

What is the magnitude of the total force on the HCl molecule due to the Na+ ion |FHCl|?

_________N

3)Compare your previous answer to the force on a single Cl- ion with charge -1e due to the Na+ ion 2.7 nm away.

What is the ratio of the force on the Cl- ion to the force on the HCl molecule |FCl-/FHCl|?

_________

Explanation / Answer

a)

dipole moment (P) =q*d

b)

The electric field due to dipole E =2kP/d3

                                              =2*9*109(0.0359E-28)/(2.7*10-9)3=0.6462/19.683 *108 =3.283*106N/C

The force of HCL (F1) =qE =(1.6*10-19)(3.283*106N/C) =5.25*10-13N

Now the force between cl- and Na+ is given by

F2 =9*109*(1.6*10-19)(1.6*10-19)/(2.7*10-9)2=1.17*10-11N

Now the ratio of forces is given by

F1/F2 =1.17*10-11N/5.525*10-13N =21.17

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