Question 13 of 13 ncorrect Map A sapling earning Two skydivers are holding on to

Question

Question 13 of 13 ncorrect Map A sapling earning Two skydivers are holding on to each other while falling straight down at a common terminal speed of 52.30 m/s. Suddenly, they push away from each other. Immediately after separation, the first skydiver (who has a mass of 89.30 kg) has the following velocity components (with "straight down" corresponding to the positive z-axis): 1,2 52.30 m/s 4.930 m/s 3.750 m/s 1 x What are the X- and y components of the velocity of the second skydiver, whose mass is 63.20 kg, immediately after separation? Number 6.966 2,x Number 5.299 What is the change in kinetic energy of the system? Number 2199.1145 Joules AD Previous 8 Give Up & View Solution Check Answer Next Exit

Explanation / Answer

apply law of conservation of momentum

aLONG X-axis

(m1+m2)*0=(89.3*4.93)+(63.2*V2,x)

V2,x = 6.966 m/s

along Y-axis

0 = (89.3*3.75)+(63.2*V2,y)

V2,y = 5.299 m/s

inityial kinetic energy is 0.5*(89.3+63.2)*52.3*52.3 = 208565.8625 J

final kinetic enertgy of the first body is 0.5*63.2*(5.299^2+6.966^2) = 2420.704 J

of the second body is 0.5*89.3*(4.93^2_3.75^2+52.3^2) = 123843.80291 J

fial kinetic energy of the systm is 123843.80291+ 2420.704 = 126264.50691 J

change in kinetic energy is 208565.8625-126264.50691 = 82301.35559 J

Related Questions

Navigate

• Browse (All)
• Browse Q
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.