A box starts at rest on a rough surface and is pulled to the right by a string.
ID: 1335402 • Letter: A
Question
A box starts at rest on a rough surface and is pulled to the right by a string. The string tension is 250.N. The friction force is 50.0N. How many Newtons is the net force and in what direction is it? If the box had more mass, the normal force would be greater. If the tension remained the same, would the net force stay the same, be more, or be less than you calculated in part a? If the box is pulled 15.0m, how much work did the tension do, and is that work positive or negative? If the box is pulled 15.0m, how much work did the friction do, and is that work positive or negative? You've just calculated the work done by each horizontal force, so calculate the net work done. Since the box cannot move vertically and cannot gain PE, how many Joules of KE did the box gain from this work? If the box is 25.0kg, at what speed is it going after this work? If conservative forces are doing work, that work is equal to the change in the mechanical energy (Delta KE + Delta PE) of the system. If only conservative forces (gravity) are doing work, then theExplanation / Answer
a)
net force = F - f
net force = 250 - 50
net force = 200 N
b)
for greater normal force ,
frictional force will be greater which gives net force to be smaller
c)
work done by tension = F * d
work done by tension = 250 * 15
work done by tension = 3750 J
d)
for the frictional force
work done by friction = -50 * 15
work done by friction = -750 J
the work done by friction is -750 J
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