An ion having charge +6 e is traveling horizontally to the left at 8.30 km/s whe

Question

An ion having charge +6e is traveling horizontally to the left at 8.30 km/s when it enters a magnetic field that is perpendicular to its velocity and deflects it downward with an initial magnetic force of 6.84×1015 N .

Part A: what is the direction of this field?

-The field is directed out of the screen

-The field is directed into the screen

-The field is directed to the right

-The field is directed to the left

Part B: what is the magnitude of this field?

B=             T

A circular coil of wire 8.80 cm in diameter has 14.0 turns and carries a current of 2.80 A . The coil is in a region where the magnetic field is 0.630 T .

What orientation of the coil gives the maximum torque on the coil ?

Please, enter the value of the angle between the field and the normal to the plane of the loop.

= _________ o

Part B

What is this maximum torque in part (A) ?

max = _______Nm

Part C

For what orientation of the coil is the magnitude of the torque 71.0 % of the maximum found in part (B)?

Please, enter the value of the angle between the field and the normal to the plane of the loop.

= _________ o

Explanation / Answer

Here ,

as the magnetic force is given as

F = q * ( V X B )

for the force on the charge is downwards

ion is moving to the left

the direction of field is INTO THE SCREEN

6.84 *10^-15 = 6 * 1.602 *10^-19 * 8300 * B

B = 0.857T

the magnitude of magnetic field is 0.857 T

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