Hammer weight-7,440 lb Free-fall distance 3.5 feet Average penetration = 1.90\"
ID: 1335924 • Letter: H
Question
Hammer weight-7,440 lb Free-fall distance 3.5 feet Average penetration = 1.90" S+ 0.10) 2000 P = Bearing capacity in tons. W Weight of hammer to nearest pound. H- Free-fall distance of hammer to nearest 0.1 foot SAverage penetration of pile to nearest 0.01 inch P= 130 T 52086 (O.b1+616) 2000 200.6 tenths PROBLEM6 Calculate the aggregate delivered to a stockpile in tons per hour. Test Data: Length of conveyor belt = 80 ft Capacity of belt 40 lb/ft Time required for one revolution 2 min 40 sec 34 nearest whole number Rate = T/hr PROBLEM 7 Determine the volume of the following concrete structure. V- Al (end area x length) A box that measures 5.2 ft x 3,8 ft x 21 ft A box that measures 5.2 ft x 3.8 ft x 2.1 ft cu ft hundredths PROBLEM8 Determine the volume of the following concrete structure. V- Al (end area x length) A Portland Cement Concrete footing that measures 2.25 ft x 2.1 ft x 3.1 yd. hundredths 3.4yExplanation / Answer
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