A box of mass 3.06 kg slides down a rough vertical wall. The gravitational force

Question

A box of mass 3.06 kg slides down a rough vertical wall. The gravitational force on the box is 30 N . When the box reaches a speed of 2.5 m/s , you start pushing on one edge of the box at a 45? angle (use degrees in your calculations throughout this problem) with a constant force of magnitude Fp = 23 N , as shown in (Figure 1) . There is now a frictional force between the box and the wall of magnitude 13 N . How fast is the box sliding 2.8 s after you started pushing on it?

A/ Find the box's speed vf at 2.8 s after you first started pushing on it.

Explanation / Answer

at the time the force is applied, t = 0

v1 = 2.5 m/s

Net force acting in y-direction,

Fnety = Weight - FP*cos(45) - Friction

m*a = 30 - 23*cos(45) - 13

3.06*a = 0.736

a = 0.736/3.06

= 0.24 m/s^2

now Apply, v2 = v1 + a*t

= 2.5 + 0.24*2.8

= 3.172 m/s <<<<------------------Answer

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