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Two insulating spheres have radii 0.300 cm and 0.500 cm, masses 0.250 kg and 0.7

ID: 1336085 • Letter: T

Question

Two insulating spheres have radii 0.300 cm and 0.500 cm, masses 0.250 kg and 0.700 kg, and uniformly distributed charges of -2.00 µC and 5.00 µC. They are released from rest when their centers are separated by 1.00 m.

(a) How fast will each be moving when they collide? (Hint: Consider conservation of energy and of linear momentum.)
m/s (lighter sphere)
m/s (heavier sphere)
(b) If the spheres were conductors, would the speeds be greater or less than those calculated in part (a)? (Note: Assume a reference level of potential V = 0 at r = .)

Explanation / Answer

let

m1 = 0.25 kg

m2 = 0.7 kg

q1 = -2 micro C

q2 = 5 micro C

initail distance between the sphere, d1 = 1m

final distance between the sphere, d2 = 0.3+0.5

= 0.8 cm

= 0.008 m


a) let v1 and and v2 are velocities of m1 and m2 when they collide

Apply conservation of momentum

0 = m1*v1 + m2*v2

v1 = (m2/m1)*v2

= (0.7/0.25)*v2

= 2.8*v2

now Apply conservation of energy

kKEi + Ui = KEf + Uf

0 + k*q1*q2/d1 = 0.5*m1*v1^2 + 0.5*m2*v2^2 + k*q1*q2/d2

0.5*m1*(2.8*v2)^2 + 0.5*m2*v2^2 = k*q1*q2*(1/d1 - 1/d2)

0.5*0.25*7.84*v2^2 + 0.5*0.7*v2^2 = 9*10^9*(-2)*5*10^-12*(1/1 - 1/0.008)

1.33*v2^2 = 11.16

v2 = sqrt(11.16/1.33)

= 2.9 m/s (heavier sphere)

v1 = 2.8*v2

= 2.8*2.9

= 8.4 m/s (lighter sphere)

b) same.

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