A suitcase of 10 kg is being towed along a rough horizontal floor by a force F,

Question

A suitcase of 10 kg is being towed along a rough horizontal floor by a force F, as shown in the figure below. The magnitude of the force F is 50 N, = 30o . The coefficient of kinetic friction between the suitcase and the floor is 0.13. The suitcase starts from rest and is towed for 20m along the floor.  

Part A - Calculate the work done by the normal force.

Part B - Calculate the work done by the towing force.

Part C - Calculate the work done by the gravitational force.

Part D - Calculate the work done by the kinetic frictional force

Part E - Apply the WORK-KE theorem to find the final speed of the suitcase.

Part F - Apply the WORK-KE theorem (alternate form) to find the final speed of the suitcase.

Explanation / Answer

part A)

as the normal force is perpendicular to direction of motion

as the work done by the normal force = 0 J

part B)

Work done by towing force = F * d * cos(theta)

Work done by towing force = 50 * 20 * cos(30)

Work done by towing force = 866.03 J

part C)

as the height of suitcase is same

Work done by gravitational force = 0 J

part D)

work done by frictional force = -Friction * d

work done by frictional force =- 0.13 * (10 * 9.8 - 50 * sin(30) )* 20

work done by frictional force = -190 J

the work done by frictional force is -190 J

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