A high-speed meteoroid moves past the Earth along an (almost) straight line. The

Question

A high-speed meteoroid moves past the Earth along an (almost) straight line. The mass of the meteoroid is 160 kg, its speed relative to the Earth is 52 km/s, and its distance of closest approach to the center of the Earth is 1.28x10^4 km.

(a) What is the angular momentum of the meteoroid in the reference frame of the Earth (The origin is at the center of the Earth.)? kg·m2/s

(b) What is the angular momentum of the Earth in the reference frame of the meteoroid (The origin is at the center of the meteoroid.)? kg·m2/s

Please show your work. Thank you.

Explanation / Answer

a) we know, angular momentum = m*v*R

= 160*52*10^3*1.28*10^7

= 1.065*10^14 kg.m^2/s

b) same. i.e 1.065*10^14 kg.m^2/s (but in opposite direection)

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