Find the velocity of m_1 after 1 80 s. A car is traveling at 47.0 mi/h on a hori

Question

Find the velocity of m_1 after 1 80 s. A car is traveling at 47.0 mi/h on a horizontal highway. If the coefficient of static friction between road and tires on a rainy day is 0.096, what Is the minimum distance in which the car will stop? What is the stopping distance when the surface is dry and mu_s = 0.599? In order to determine the coefficients of friction between rubber and various surfaces, a student uses a rubber eraser and an incline. In one experiment begins to slip down the incline when the angle of inclination is 35.1 degree and then move, down the iodine with constant speed when the angle is reduced to these data, determine the coefficients of static and kinetic friction for this experiment.

Explanation / Answer

Given that

The initial velocity of the car (u) = 47mi/h =47(0.447) =21.009m/s

Then the final velocity of the car (v) =0m/s

A)

Given that the coefficient of static friction is us =0.096

Now the acceleration is given by a =-usg =-0.096*9.81 =-0.941m/s2

We know that from the equation of motion v2-u2 =2as

The stopping distance is given by s =v2-u2/2a =0 -(21.009)2/2*(-0.941) =234.526m

B)

Given that

The coefficient of static frcition is us =0.599

Acceleration is given by a =-usg =-5.876m/s2

We know that from the equation of motion v2-u2 =2as

The stopping distance is given by s =v2-u2/2a =0 -(21.009)2/2*(-5.876) =37.55m

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