go through the five eceerations again, ehoosing only members of your now popalat
ID: 133727 • Letter: G
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go through the five eceerations again, ehoosing only members of your now popalation. nitial eenotype F genotype After ive generations, genotype in table 20.9 T's genotype Teble 20. SE dominant Compare table 20,9 with table 20.8. Do the results suggest that the size of the population affects genetic The term genetic drift is applied to situations in which chance alone cause Genetie drift is usually more pronounced in small populations than in large populatioes. Genetic drift is a meams by which evolution occurs. Evolution is sometimes defined as a in gene pool frequencies Laboratory Review 20 1. What is the genotype of a man who has free earlobes but wihvove mothet has at- tached carlobes? 2. A woman who is not color blind has a color-blind son. What is the genotypeof this woman? 4. A man with blood type AB never could be the father of a child with blood type 5. Can two parents who cannot taste PTC have children who can taste PTC? 7. If the man is heterozygous but the woman is homozygous recessive, what are the chances that their child will be homozygous dominant? 8. In question 7, what are the chances that the child will be like the father? 9. If it is impossible for a color-blind boy to determine by inspection which parent is responsible for the color blindness, which parent would it be? 10. If the blood type is A, the individual could be AA or Reference Trelease, et al. 1980. Biology 101. Dubuque, lowa: Kendall/Hunt Publishing Company. Films and Videos The instructor's manual for Inquiry into Life contains suggestions for films that could be shown during this laboratory 20-10Explanation / Answer
1) Free earlobes are transmitted in an autosomal dominant fashion. Therefore, the genotype of man who has a free earlobe whose mother is affected (ee) would be Ee. The man in question would be heterozygous with the genotype Ee.
2) Color blindness is transmitted in X linked recessive pattern. A woman who is not color blind has a color blind son. Therefore, the mother should be carrier of color blindness gene with the genotype Xx.
3) If p is 0.8, then q is 0.2 because p+q is 1.
4) The blood group alleles A and B are both codominant. So, a man with blood type AB could never be a father of O blood group child.
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