Three point charges are arranged as shown. Find magnitude and direction of the n

Question

Three point charges are arranged as shown. Find magnitude and direction of the net electric field at the origin. An electron travelling with initial velocity v rightarrow = 2 Times 10^4i m/s enters a region of uniform electric field E rightarrow = 10i N/C. What is the magnitude and direction of the acceleration experienced by the electron? How far will it travel in the +x-direction before coming to a stop? Two equally charged, 1.00 g spheres are placed with 2.00 cm between their centers. When released, each begins to accelerate at 225 m/s^2. What is the magnitude of the charge on each sphere? 100 nC 200 nC 300 nC 400 nC 500nC

Explanation / Answer

here,

electric feild due to charge q , E = k*q/r^2

the net electric feild in the y direction , Ey = K*2*10^-6 / 1^2 + k*2*10^6 / 1^2

Ey = 36*10^3 N/C

the net electric feild in x direction , Ex = - k * 5 * 10^-6 /2^2

Ex = 11.25 *10^3 N/C

the net electric feild , E = sqrt(Ex^2 + Ey^2)

E = 37.72 *10^3 N/C

theta = arctan(Ey/Ex)

theta = arctan( 36 / 11.25)

theta = 72.65 degree

the magnitude of electric feild at the origin is 37.72*10^3 N/C and 107.35 degree from the + x axis in counter clockwise direction

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