A student stands at the edge of a cliff and throws a stone horizontally over the

Question

A student stands at the edge of a cliff and throws a stone horizontally over the edge with a speed of

The cliff is h = 34.0 m above a flat, horizontal beach as shown in the figure.

(a) What are the coordinates of the initial position of the stone?

(b) What are the components of the initial velocity?

(c) Write the equations for the x- and y-components of the velocity of the stone with time. (Use the following as necessary: t. Let the variable t be measured in seconds. Do not include units in your answer.)

(d) Write the equations for the position of the stone with time, using the coordinates in the figure. (Use the following as necessary: t. Let the variable t be measured in seconds. Do not state units in your answer.)

(e) How long after being released does the stone strike the beach below the cliff?
(s)

(f) With what speed and angle of impact does the stone land?

Explanation / Answer

Here ,

a) initial poistion of the stone ,

x0 = 0 m

y0 = h = 34 m

b)

as the initial velocity is horizontal

v0x = 17.5 m/s

v0y = 0 m/s

c)

as there is no acceleration in x - dirextion

Vx = 17.5 m/s

for velocity in y direction , using first equation of motion

Vy = -9.8 * t

d)

x = Vx * t

x = 17.5 * t

for y

y = 0.5 * a *t^2 + y0

y = 34 - 0.5 * 9.8 * t^2

y = 34 - 4.9 * t^2

e)

for reaching the ground ,

y = 0

34 - 4.9 t^2 = 0

t = 2.63 s

the time taken for the stone to reach ground is 2.63 s

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