sapling learning Two skydivers are holding on to each other while falling straig
ID: 1339057 • Letter: S
Question
sapling learning Two skydivers are holding on to each other while falling straight down at a common terminal speed of 58.30 m/s Suddenly, they push away from each other. Immediately after separation, the first skydiver (who has a mass of 94.80 kg) has the following velocity components (with "straight down" corresponding to the positive z-axis) 4430m/s Vi,-4.750 m/s -58.30 m/s What are the x- and y-components of the velocity of the second skydiver, whose mass is 57.70 kg immediately after separation? Number m/s 2-x Number m/s What is the change in kinetic eergy of the system? Number JoulesExplanation / Answer
as we know in the absence of external forces, linear momentum of the system remains conserved.
initial momentum = (m1 + m2)*v
P1 = (94.80 + 57.70)*58.30 k
P1 = 8890.75 k
final momentum = m1*v1 + m2*v2
P2 = 94.80[4.430 I + 4.750 J + 58.30 k] + 57.70*v2
P1 = P2
8890.75 k = 419.964 i + 450.3 j + 5526.84 k + 57.70*v2
57.70 v2 = - 419.964 i - 450.3 j + 3363.91 k
v2 = - 7.27 i - 7.80 j + 58.3 k
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