A 95 kg football player runs straight up the field at 7.2 m/s. He is tackled by

Question

A 95 kg football player runs straight up the field at 7.2 m/s. He is tackled by a 119 kg player running across the field at an angle of 35° to the horizontal at 5.8 m/s. In what direction (in degrees) and at what velocity will they move together immediately after impact? (The direction should be measured relative to the direction straight up the field: For instance, if both players kept moving straight up the field, we would say that the direction was 0 degrees; if they moved directly across the field, we would call that direction 90 degrees.)

Explanation / Answer

Here ,

let the final velocity is v

as they stick together after the collision

Using conservation of momentum

95 * 7.2 j + 119 * 5.8 * ( cos(35) i + sin(35) j ) = (95 + 119) * v

v = 5.056 j + 2.64 i m/s

v = sqrt(5.056^2 + 2.64^2) at arctan(5.056/2.64) degree

v = 5.704 m/s at 62.4 degree with the horizontal

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