If you follow a diet of 2030 food calories per day (2030 kilocalories), what is

Question

If you follow a diet of 2030 food calories per day (2030 kilocalories), what is your average power consumption in watts? (A food or "large" calorie is a unit of energy equal to 4.2 times 10^3 J; a regular or "small" calorie is equal to 4.2 J) How many days of a diet of 2030 large calories are equivalent to the gravitational energy change from sea level to the top of Mount Everest, above sea level? Assume your mass is 67 kg. (the body is not anywhere near 100% efficient in converting chemical energy into change in altitude.)

Explanation / Answer

2030Kcal per day

2030*10^3*4.2 J per day

2030*10^3*4.2 / (24*3600) J/s

power consumption = 98.68 watt ( almost equal to 100 watt bulb)

b)

gravitational energy = mgh = 67*9.8*8848 = 5809596.8 joule

no of days = (5809596.8)/(2030*10^3*4.2) = 0.681 day

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