A 0.18 kg What is the average speed of an oxygen molecule (M = 32) in the air wh

Question

A 0.18 kg What is the average speed of an oxygen molecule (M = 32) in the air when the temperature is 10.0 degree C = 283 K? A 0.18 kg cube of ice melts into a puddle of titer at 0 degree C. What is the change in entropy? The surface of the Earth is warmer than it would be if the Earth had no atmosphere. Why? The atmosphere insulates heat transfer upward. The atmosphere radiates heat downward. Clouds reflect sunlight. Clouds absorb sunlight. Sunlight adds heat to the atmosphere. If we heat 2500 moles of air 6.00 degrees K at a

Explanation / Answer

Heat Needed to melt the ice , Q_ice = m_ice *Hf
m_ice = 0.18 Kg = 180 g
Hf = 333.55J/g  
Q_ice = 333.55J/g * 180 g
Q_ice = 60039 J

Change in Entropy = Q_ice / 273 J/K
Change in Entropy = 60039/273 J/K
Change in Entropy = 220 J/K

Correct Option = (E)

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