1)A jet airplane is in level flight. The mass of the airplane is m = 9010 kg. Th
ID: 1340136 • Letter: 1
Question
1)A jet airplane is in level flight. The mass of the airplane is m = 9010 kg. The plane travels at a constant speed around a circular path of radius R = 9.77 miles and makes one revolution every T = 0.129 hours. What is the magnitude of the lift force acting on the plane? At what angle is the airplane banked?
2)A heavy sled is being pulled by two people as shown in the figure. The coefficient of static friction between the sled and the ground is s = 0.619, and the kinetic friction coefficient is k = 0.427. The combined mass of the sled and its load is m = 276 kg. The ropes are separated by an angle = 29°, and they make an angle = 31.8° with the horizontal. Assuming both ropes pull equally hard, what is the minimum rope tension required to get the sled moving? If this rope tension is maintained after the sled starts moving, what is the sled's acceleration?
Explanation / Answer
The lift force acts perpendicular to the wings.Let its magnitude be F. Also let the plave be banked at an angle a.
vertical component of F = F * cos a. It must equal to the weight of the plane (mg)
horizontal component of F = F*sin a. It must equal mv^2 / R
R = 9.77 miles = 9.77*1609.34 m = 15723.29 m
V= 2*pi*R/t = 2*pi*15723.29 / (0.129*3600) = 212.73 m/s
From above:
F * cos a = m*g
F*sin a = m*V^2/R
Divide 2nd equation by 1st one:
tan a = V^2/(R*g)
tan a = (212.73)^2 / (15723.29 * 9.8) =0.294
a=16.37 degree
Banking angle = 16.37 degree
use 1st equation to get F
F * cos a = m*g
F* cos (16.37) =9010*9.8
F=92027 N
Lift= 92027 N
I am allowed to answer only 1 question at a time
Also in 2nd question figure is not attached
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