A 5kg sample of the obsidian (same rock as above) warms in the summer sun from 5

Question

A 5kg sample of the obsidian (same rock as above) warms in the summer sun from 50 degrees F in the early morning to 80degrees F by mid day. 1.How much heat is absorbed by the rock ? A 5kg sample of the obsidian (same rock as above) warms in the summer sun from 50 degrees F in the early morning to 80degrees F by mid day. 1.How much heat is absorbed by the rock ? 1.How much heat is absorbed by the rock ? 2 nearby is a pool of water also at 50 degrees F in the morning. If the water absorbs the same about of heat as the rock what is the final temperature of the water ?
Please mark the answers in numerical order (if it's 1 or 2 ) Material Tested: Data Table Material PVC Steel lmw 2 213. 2442a72 32 Alblock1a2.lylzunen 20. Al plates Al cylinder Obsidiane Wood |W" | 22.-0ig We will be using the data above to answer below QUESTIONS A 5 kg sample of the obsidian (same rock as above) warms in the summer sun from 50° F in the early morning to 80° F by mid-day. NOTE: Be careful with the temperatures and other units 1. How much heat is absorbed by the rock? 2. Nearby is a 5 L pool of water, also at 50° F in the moming. If the water absorbs the same amount of heat as the rock, what is the final temperature of the water?

Explanation / Answer

1)We know that ,q=mc(dt)

Which means the heat transfered is equal to mass times specific heat times change in temperature. This is for a change within the same phase

From 50 to 800 F,
q=(0.005g)(0.2 J/g0F)(800F-500F)=0.03 kJ

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