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home / study / questions and answers / science / physics / three beads are placed on the vertices of an equilateral... Your question has been answered! Rate it below. Let us know if you got a helpful answer. Question Three beads are placed on the vertices of an equilateral triangle of side d = 1.7 cm. The first bead of mass m1 = 110 g is placed on the top vertex. The second bead of mass m2 = 65 g is placed on the left vertex. The third bead of mass m3 = 95 g is placed on the right vertex.

Part (a) Write a symbolic equation for the horizontal position of the center of mass relative to the left vertex of the triangle.

Part (b) Calculate the numeric value of the location of the horizontal component of the center of mass relative to the left vertex in cm.

Part (c) Write a symbolic equation for the location of the vertical component of the center of mass relative to the base of the triangle.

Part (d) Calculate the numeric value of the vertical component of the center of mass relative to the base of the triangle in cm.

this is not part of the question. i tried to write the equation but there is no option to put x/y in the answer. the only options i have are aplha, beta, theta, a,d,g,h,j,k,m,m1,m2,m3,P and t

Explanation / Answer

total mass m = m1 + m2 + m3

= 110+ 65 + 95

= 270 g

Part (a)

a symbolic equation for the horizontal position of the center of mass relative to the left vertex of the triangle

= (m1 X 1/2 X d + m3 * d) / m

= (110X0.5X1.7+95X1.7)/270

= 255/270

= 0.944 cm

Part b

the numeric value of the location of the horizontal component of the center of mass relative to the left vertex in cm = (110X0.5X1.7 +95X1.9) / 270

= 0.944cm

Part C

a symbolic equation for the location of the vertical component of the center of mass relative to the base of the triangle

= m1 X (3/2) X d / m

Part D

the numeric value of the vertical component of the center of mass relative to the base of the triangle in cm

= 110 X 0.866 X 1.7 / 270

= 161.942 / 270

= 0.599 cm

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