edwh in the Phen Name: Mavam Estvnda Day/Time:10:30M HOMEWORK EXTRA CREPt -Snhu

Question

edwh in the Phen Name: Mavam Estvnda Day/Time:10:30M HOMEWORK EXTRA CREPt -Snhu pu Due wedresdoy Inheritance of two traits 1. Freckles (F) and the ability to roll your tongue (T) are both dominant traits. If a person is heterozygous for both traits what kinds of gametes can they produce? If a person homozygous dominant for freckles and heterozygous for tongue rolling has a child with a person heterozygous for freckles, but who cannot roll their tongue what are the possible phenotypes of the child? (show work) 3. If persons with the genotypes FfTt and ffTt have a child, what are the chances the child will not have freckles nor be able to roll their tongue? 4. If persons heterozygous for both traits have a child, what are the chances the child will have a homozygous dominant genotype for both traits?

Explanation / Answer

Answer:

1) FfTt genotype can produce 4 types of gametes, FT, Ft, fT & ft.

2). FFTt x Fftt

Freckles, rolling = 1/2 or 50%

Freckles, no rolling = 1/2 or 50%

3). FfTt x ffTt

Ff x ff = Ff (1/2)-Freckles & ff(1/2)-no freckles

Tt x Tt = T_ (3/4)-Rolling & tt (1/4) -no rolling

The chance of child that will not having freckles and nor be able to roll their tongue = fftt = 1/2 * 1/4 = 1/8

4). FfTt x FfTt

Ff x Ff = FF(1/4), Ff (1/2) & ff(1/4)

Tt x Tt = TT (1/4), Tt(1/2) & (1/4)

The chance that the child will have homozygous dominant genotype for both traits = FFTT = 1/4 * 1/4 = 1/16

Ft ft FT FFTt (freckles, rolling) FfTt (freckles, rolling) Ft FFtt (freckles, no rolling) Fftt (freckles, no rolling)

Related Questions

Navigate

• Browse (All)
• Browse E
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.