Hint: Use the feet of the climber as the center of rotation when calculating tor

Question

Hint: Use the feet of the climber as the center of rotation when calculating torque.

____________ N

What is the horizontal force exerted by the climber's feet?

_______________N

What is the total vertical force exerted by the climber's hands and feet?

_______________N

The horizontal force depends on the distance of the climber's center of gravity from the wall. What should that distance be if the climber wants to reduce the required horizontal force from hands by 50%? (Use DNE if no solution is possible.)

______________m

What should the distance of center of gravity from the wall be if the climber wants to reduce the vertical force of her hands and feet by 50%? (Use DNE if no solution is possible.)

_______________m

Explanation / Answer

A)
Using the feet of the climber as the center of rotation and balancing torque
torque due to weight = torque due to force
64*g*0.44 = F*1.52
64*9.8*0.44 = F*1.52
F= 181.6 N (towards right)
B)
Let this force be F
net horizontal force should be 0
So F must balance 181.6 N
F= 181.6 N (towards Left)
C)
Climber feet and applies a force F upward
it must balance m*g
F= m*g
= 64*9.8
=627.2 N

D)
Using the feet of the climber as the center of rotation and balancing torque
Let distance be d
Force is 181.6/2=90.8 N
torque due to weight = torque due to force
64*g*d = 90.8*1.52
64*9.8*d = 90.8*1.52
d=0.22 m
Answer: 0.22 m

E)
Vertical force depends on m*g
So its not possible
Answer : DNE

Related Questions

Navigate

• Browse (All)
• Browse H
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.