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1a) Two capacitors, each 10 Farads, are connected together to create a 5 Farad c

ID: 1343122 • Letter: 1

Question

1a) Two capacitors, each 10 Farads, are connected together to create a 5 Farad capacitor. They must be connected in:

1b.) A dielectric:

1c.) The bigger the capacitance, the

1d.) You increase the voltage across a parallel plate capacitor (e.g., you turn up the voltage knob on a power supply). You have:

1a) Two capacitors, each 10 Farads, are connected together to create a 5 Farad capacitor. They must be connected in:

A) parallel
B) neither series nor parallel
C) either series or parallel
D) series

1b.) A dielectric:

A) is a conductor and increases the capacitance when put between the plates of a capacitor
B) is an insulator and decreases the capacitance when put between the plates of a capacitor
C) is an insulator and increases the capacitance when put between the plates of a capacitor
D) is a conductor and decreases the capacitance when put between the plates of a capacitor

1c.) The bigger the capacitance, the

A) more charge on its plates for a given potential difference between its plates
B) electric field between the plates
C) greater potential difference between the plates independent of the charge on the plates
D) greater the potential difference across its plates, for a given charge on the plates
E) more charge on the plates independent of the potential difference across the plates

1d.) You increase the voltage across a parallel plate capacitor (e.g., you turn up the voltage knob on a power supply). You have:

A) Increased the charge on the capacitor, not changed the capacitance of the capacitor
B) Decrease the charge on the capacitor, not changed the capacitance of the capacitor
C) Decreased the capacitance of the capacitor, not changed the charge on the capacitor
D) Increased the capacitance of the capacitor, not changed the charge on the capacitor
E) Not changed either the capacitance nor the charge on the capacitor

Explanation / Answer

Here ,

1a) for the capacitance , C = 10 F

C1 = 5 F

Now , for half capacitance

as the net capacitor is less than indivisual capacitance

Ceq = C/2

Ceq = 10/2 = 5 F

they nust be connected in D) series

1b)

for a dielectric :

C) is an insulator and increases the capacitance when put between the plates of a capacitor

1c)

as Q = C * V

A) more charge on its plates for a given potential difference between its plates

1d)

as the capacitance is independent of th voltage

ans the charge = C * V

A) Increased the charge on the capacitor, not changed the capacitance of the capacitor

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