A 32.0-kg block is resting on a flat horizontal table. On top of this block is r

Question

A 32.0-kg block is resting on a flat horizontal table. On top of this block is resting a 14.0-kg block, to which a horizontal spring is attached, as the drawing illustrates. The spring constant of the spring is 315 N/m. The coefficient of kinetic friction between the lower block and the table is 0.450, and the coefficient of static friction between the two blocks is 0.720. A horizontal force is applied to the lower block as shown. This force is increasing in such a way as to keep the blocks moving at a constant speed. Determine the amount by which the spring is compressed at the point where the upper block begins to slip on the lower block.

Explanation / Answer

upper block will slip if static frictional forec equals force of spring
or,
k*x = miu*m2*g
315*x = 0.72*14*9.8
x=0.3136 m
= 31.36 cm
Answer: 31.36 cm

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