v Lab 8 Prelab AC Cu x GA coil of wire with a x eCharlottesville Food X E Jasmin

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v Lab 8 Prelab AC Cu x GA coil of wire with a x eCharlottesville Food X E Jasmine Amanin x M (no subject -jic4xm x CHome Chegg.com x Mastering Physics: CCX gwan x C t/web/Student/Assig dep 12231932 VPA VPa Vmar, the signal generators ampltude (or magnitude or peak voltage is set to 4.23V and f the generators frequency, is set to 47.3Hz. a) The impedance of the cincuit is: e of the voltage across R is: c) The amplitude of the votage across C is: X V d) The phase shift between the current through the circuit and the driving voltage is: The frequency is in:reased to 785Hz. e Tempedance of the circuit The amplitude of the votage across Ra is: g) The amplitude of the votage across c is: h) The phase shift between the current through the cincuitandthe driving voltage is: 2) Following Activit 3 ir the capacitor is replaced by 839 mH inductor(L) ,the signal generators ampitude (or magninoe peak voltage is the same, VPa frequency is lowered back to 47.3 Hz. The The impedence of the circuit is: X n J) The amplitude of the votage acrosE Ro is: The ampitude of the votege across L is: The phase shift between the current through the circuit and the driving vobage ir The frequency is again increased to 785 Hz. m) The impedance of the circuit ir n The amplitude of the votege across Ro is: The de of the voltage across List p The phase shift between the current through the cicuit and the driving voltage is: NOTE: The calculations you just performed are nearly identical to the measurements and comparisons you wil be doing in the lab, A 3:46 PM 4x E 0/25/20 Ask me anything

Explanation / Answer

a) Z = sqrt(R^2 + Xc^2 )

Xc = 1 / 2pifC = 1 / (2 x pi x 47.3 x 482 x 10^-9) = 6980 ohm

and R = 522 Ohm

Z = 7000 ohm

b) i = V/ Z = 4.29 / 7000 =6.13 x 10^-4 A

VR = iR = 0.320 A

c) Vc =i XC = 4.28 A

d) @ = tan-1(Xc / R) = -85.72 deg

e) Xc = 1 / 2pifC = 1 / (2 x pi x 785 x 482 x 10^-9) = 420.63ohm

R = 522 ohm

Z = sqrt(420.63^2 + 522^2) = 670.38 ohm

f) i = V / Z = 4.29 / 670.38 =6.40 x 10^-3 A

VR0 = i R = 3.34 V

g) Vc =i Xc = 6.40 x 10^-3 x 420.63 = 2.69 V

h) @ = tan^-1( Xc /R) = - 38.86

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