Exercise 10.34 An airplane propeller is 2.48 m in length (from tip to tip) and h
ID: 1346668 • Letter: E
Question
Exercise 10.34
An airplane propeller is 2.48 m in length (from tip to tip) and has a mass of 157 kg . When the airplane's engine is first started, it applies a constant torque of 1860 Nm to the propeller, which starts from rest.
Part A
What is the angular acceleration of the propeller? Treat the propeller as a slender rod.
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Part B
What is the propeller's angular speed after making 5.00 rev ?
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Part C
How much work is done by the engine during the first 5.00 rev ?
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Part D
What is the average power output of the engine during the first 5.00 rev ?
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Part E
What is the instantaneous power output of the motor at the instant that the propeller has turned through 5.00 rev ?
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= rad/s2Explanation / Answer
given,
length = 2.48 m
mass = 157 kg
torque = 1860 Nm
moment of inertia of the rod = (1 / 12) * m * l^2
moment of inertia of the rod = (1 / 12) * 157 * 2.48^2
moment of inertia of the rod = 80.4677 kg.m^2
torque = I * acceleration
1860 = 80.4677 * acceleration
acceleration = 23.114 rad/sec^2
distance = 5 rev or 31.4159 radians
v^2 = u^2 + 2as
v^2 = 0 + 2 * 23.114 * 31.4159
v = 38.11 rad/sec
angular speed after 5 rev = 38.11 rad/sec
work = 0.5 * I * w^2
work = 0.5 * 80.4677 * 38.22^2
work done during first 5 rev = 58773.34 J
v = u + at
38.22 = 0 + 23.114 * t
t = 1.65 sec
power = work / time
power = 58773.34 / 1.65
average power output = 35620.2 W
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