A woman with mass 50 kg is standing on the rim of a large disk that is rotating

Question

A woman with mass 50 kg is standing on the rim of a large disk that is rotating at 0.80 rev/s about an axis through its center. The disk has mass270 kg and radius 4.0 m.

Part A

Calculate the magnitude of the total angular momentum of the woman–disk system. (Assume that you can treat the woman as a point.)

Express your answer to two significant figures and include the appropriate units.

448.18kgm2s

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A woman with mass 50 kg is standing on the rim of a large disk that is rotating at 0.80 rev/s about an axis through its center. The disk has mass270 kg and radius 4.0 m.

Part A

Calculate the magnitude of the total angular momentum of the woman–disk system. (Assume that you can treat the woman as a point.)

Express your answer to two significant figures and include the appropriate units.

448.18kgm2s

SubmitMy AnswersGive Up

Incorrect; Try Again; 2 attempts remaining

Explanation / Answer

angular momentum = Iw

I= moment of inertia of system = (270 x 4^2 /2) + (50 x 4^2) = 2960 kg m^2

angular velocity w = 0.80 x2pi rad/s =5.03 rad/s

angular momnetum = 2960 x 5.03 = 14878.58 kg m^2 /s

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