The vaporization of 0.900 kg of water converts 0.900 liter of liquid water at 10
ID: 1348910 • Letter: T
Question
The vaporization of 0.900 kg of water converts 0.900 liter of liquid water at 100°C into a volume of water vapor at the same temperature. The water vapor occupies a larger volume than the water; hence, during vaporization, the water must do work on the surrounding atmosphere while it expands.
(a) How much work does 0.900 kg of water do while it expands into vapor, at a pressure of 1.00 atm?
(b) Given that the heat of vaporization of water is
(c) How much work does 0.900 kg of water do while it expands into vapor, at a pressure of 2.10 atm?
(d) Deduce the heat of vaporization of water at 2.10 atm (and 100°C). Assume that the change of the density of liquid water between 1.00 atm and 2.10 atm can be neglected in this calculation.
(Answers Provided: (a) 1.55e+5J (b) 1.88e+6J (c) -1.15e+5J (d) 2.14e+6J )
(I need to know what formula to use fore each part.)
Explanation / Answer
The vaporization of 0.900 kg of water converts 0.900 liter of liquid water at 10
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