(Figure 1) shows resistors R 1 = 40.0 and R 2 = 10.0 connected in parallel to an
ID: 1349412 • Letter: #
Question
(Figure 1) shows resistors R1 = 40.0 andR2 = 10.0 connected in parallel to an AC source. The maximum current in the circuit is 2.53 A . The source emf peaks at t = 0, and the frequencyis 60.0 Hz.
Part A
What is the amplitude Emax of the AC source?
Express your answer with the appropriate units.
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Part B
What is the potential difference across resistor R1 at t = 20.2 ms ?
Express your answer with the appropriate units.
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Part C
What is the potential difference across resistor R2 at t = 20.2 ms ?
Express your answer with the appropriate units.
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Emax=Explanation / Answer
A) R1 and R2 are in parallel connection.
so equivalent of these resistance = Req
1/Req = 1/R1 + 1/R2 = 1/40 + 1/10
Req = 8 ohm
Emax = Imax Req = 2.53 x 8 = 20.24 V
B) E = Emax sin(wt)
and w = 2pif
E = 20.24 sin(2pi60t)
at t = 20.2 x 10^-3 s
E = 20.24 sin(2 x pi x 60 x 0.0202) = 19.66 V
that is the PD = 19.66 V
C) Potential diff across R1 and R2 will be same as they are connected in parallel.
PD = 19.66 V
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