The circuit below contains three light bulbs, a capacitor, and a switch. At the

Question

The circuit below contains three light bulbs, a capacitor, and a switch. At the instant shown, the switch has been open for a long time. The switch is now closed. All of the questions that Follow correspond to the moment right after the switch is closed. At this instant, the charge on the capacitor will be the same as it was when the switch was open. (a) How much charge is stored on the capacitor at this instant? Clearly indicate the positive and negative side of the capacitor in the diagram above. (b) What is the current through light bulb R1? (c) What Is the rate at which light bulb R2 is converting electrical energy into thermal energy? (d) What is the rate at which the charge on the capacitor is charging? Is the capacitor charging or discharging? Explain briefly.

Explanation / Answer

1.Q=CV=(500x10^-12)(1.5)=750x10^-12C

negative of battery connected to the positve of the capacitor

2.V=IR

I=V/R1

I=1.5/100=0.015

3.W=QV;

W=(750x10^-12)1.5=1125x10^-12

4. tau=RC=600x500x10^-12=3x10^-7

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