In the figure (Figure 1) a conducting rod of length L = 32.0 cm moves in a magne

Question

In the figure (Figure 1) a conducting rod of length L = 32.0 cm moves in a magnetic field B? of magnitude 0.450 T directed into the plane of the figure. The rod moves with speed v = 5.70 m/s in the direction shown.

A) What is the potential difference between the ends of the rod?

B) When the charges in the rod are in equilibrium, what is the magnitude of the electric field within the rod?

C) What is the potential difference across the rod if it moves parallel to ab?

D) What is the potential difference across the rod if it moves directly out of the page?

Explanation / Answer

length of the rod l=32 cm

magnetic field B=0.45 T

speed v=5.7 m/sec

a)

potential difference Vab=l*v*B

vab=32*10^-2*5.7*0.45

vab=0.821 v

b)

electric field E=v*B

E=5.7*0.45

E=2.565 N/C

direction of E is from b to a

c)

Vab=E*d

Vab=0

because, d is very small

d)

vab=0

because, v and B has the same direction

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