True or false and please explain why 4. The net magnetic force on a current loop

Question

True or false and please explain why
4. The net magnetic force on a current loop is always zero.


11. (15 points) A 2.0 meter tall man is 5.0 meters from the converging lens of a camera. His image appears on a detector that is 50mm behind the lens.
A) how tall is his image on the detector?
B) what is the focal length of the lens? True or false and please explain why
4. The net magnetic force on a current loop is always zero.


11. (15 points) A 2.0 meter tall man is 5.0 meters from the converging lens of a camera. His image appears on a detector that is 50mm behind the lens.
A) how tall is his image on the detector?
B) what is the focal length of the lens? True or false and please explain why



11. (15 points) A 2.0 meter tall man is 5.0 meters from the converging lens of a camera. His image appears on a detector that is 50mm behind the lens.
A) how tall is his image on the detector?
B) what is the focal length of the lens?

Explanation / Answer

Question 4.

Is true. To explain it better, let me put the foloowing example:

A current I is flowing in a square loop. The sides of the square have length L. Let the direction of the normal to the loop be defined by the right-hand rule. Curl the fingers of your right hand in the direction of the current flow. Your thumb points into the direction of the normal. Assume that the square loop is placed into a magnetic field and that the normal to the area is perpendicular to B as shown on the right.

The force on each side is given by F = IL × B. The current I is the same for each side, but the vector L is different for each side. The force on sides 1 and 3 is zero, since L × B is zero. The force on side 2 has magnitude F = ILB and points out of the page. The force on side 4 has magnitude F = ILB and points into the page. The total force is zero.

In a uniform magnetic field the net force on a current loop is zero.

Question 11.

I missed a formula for part B, so i'm gonna do part A:

M = hi/ho = di/do

hi = di * ho / do

hi = 5 x 0.05 / 2

hi = 0.125 m or 125 mm.

For Part b, try to post it in a new question, I don't remember the formula to use in this part.

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