The gravitational force on a baseball is -Fg [j] . A pitcher throws the baseball
ID: 1353797 • Letter: T
Question
The gravitational force on a baseball is -Fg [j] . A pitcher throws the baseball with velocity v [i] by uniformly accelerating it straight forward horizontally for a time intervalt = t 0 = t. If the ball starts from rest, determine the following: (Use any variable or symbol stated above along with the following as necessary: g for the acceleration due to gravity.)
(a) Through what distance does it accelerate before its release?
d =
vt+12at2
[Incorrect: Your answer is incorrect.]
(b) What force does the pitcher exert on the ball?
[vector F] P =
Fg
[Incorrect: Your answer is incorrect.]
Explanation / Answer
The acceleration imparted by the pitcher is v/t = vi/t. The distance moved under uniform acceleration a is 0.5*a*t² substitute for a to get
s = 0.5*(v/t)*t² = 0.5*v*t
The mass of the ball is Fg/g. The force imparted in the i direction by the pitcher is M*a. The i force component is then
Fi = (Fg/g)*0.5*v*t
The j component is +Fg (to keep the motion horizontal and counteract gravity). The total force exerted by the pitcher is then
F = [Fi² + Fg²]
The angle of the force is arctan(Fg/Fi)
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