A small block with a mass of 0.0600 kg is attached to a cord passing through a h

Question

A small block with a mass of 0.0600 kg is attached to a cord passing through a hole in a frictionless, horizontal surface (Figure 1) . The block is originally revolving at a distance of 0.31 m from the hole with a speed of 0.69 m/s . The cord is then pulled from below, shortening the radius of the circle in which the block revolves to 0.11 m . At this new distance, the speed of the block is 1.94 m/s .

What is the tension in the cord in the original situation when the block has speed v0 = 0.69 m/s ?

What is the tension in the cord in the final situation when the block has speed v1 = 1.94 m/s ?

How much work was done by the person who pulled on the cord?

Explanation / Answer

part A )

T = mv^2/r

T = 0.06*(0.69)^2/0.31

T = 0.092 N

part B )

T = mv^2/r

T = 0.06 *(1.94)^2/0.11

T = 2.05 N

part C )

by work energy theorem

change in kinetic energy = work done

w = 1/2m*(v1^2 - v0^2)

w = 0.0986 J

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