8. (10 points) A particular dihybrid cross resulted in 38 plants with smooth lea

Question

8. (10 points) A particular dihybrid cross resulted in 38 plants with smooth leaves, 82 plants with slightly rough leaves, and 44 plants with very rough leaves. Use Chi-square a incomplete dominance. analysis to determine if this data supports Table: Chi-Square Probabilities r 0.990.99 0.9750. 0.0250.01 0.005 95 0.90 0.100.05 0.0010.004 0.016 2.7 3.8415.0246.635 0.0511| 0.103] 0.211 4.605|| 5.991| 7.3781 921? 10.597 0.216 0.352 0.5846.25 7.815 9.348345 12.838 4 0.207 0.297 0.4840.0647.7799.488 143 13.277 14.860 412 0.554 0.831 1.145610 9.236 11.070 12.833 15.086 16.750 6/ 0.6761 0.8721 1.2371 1.635| 2.2? 10.645| 12.59? 14.449 16.812| 18.548 2/ 0.01? ?- 0.072 ? 7.815| 9.348 11.345| 12.838 0. 115m 0 216 0.352 0 584 6.251 0.989 239 6902.16 2.833] 12.01? 14.067 16.013 18.475| 20.278 1.646 2.180 2.733 3.490 13.362 15.507 17.535 20.090 21.955 3.325 4.168 14.684 16.919 19.023 21.666 23.589 101 2.156/ 2.558| 3.247| 3.940| 4.865| 15.98? 18.30? 20.483] 23.209|| 25.188 91.735 2.088 2.7

Explanation / Answer

Degree of freedom n-1 = 3-1 = 2

Chi square table at 95% = 5.991

Chi square table > Chi square observed value.

So it is accepted it is incomplete dominance

Observed Expected O-E (O-E)2 (O-E)2 / E smooth 38 1/4 X 164 = 41 -3 9 0.21 Rough 82 2/4 x 164 = 82 0 0 0 very rough 44 1/4 X 164 = 41 3 9 0.21 Total 164 0.42

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