1) A 4.25-kg block is sent up a ramp inclined at an angle = 36.5° from the horiz
ID: 1358751 • Letter: 1
Question
1) A 4.25-kg block is sent up a ramp inclined at an angle = 36.5° from the horizontal. It is given an initial velocity v0 = 15.0 m/s up the ramp. Between the block and the ramp, the coefficient of kinetic friction is k = 0.444 and the coefficient of static friction is s = 0.790. How far up the ramp (in the direction along the ramp) does the block go before it comes to a stop?
2)A 6-kg box is pushed 15 m across a level floor by a constant 11.15-N applied force. The coefficient of kinetic friction between the box and the floor is 0.13.
a)Assuming the box starts from rest, what is the final velocity of the box at the 15-m point?
b)If there were no friction between the box and the floor, what applied force would be required to give the box the same final velocity as calculated above?
Explanation / Answer
As block is moving so kinetic friction will work.
KInetic friction f =uk N = uk mgcos36.5
f = 0.444 x m x 9.81 x cos36.5 = 3.50m
Using work energy theorem,
work done by Gravity + work done by friction = change in KE
- mgLsin36.5 - f x L = 0 - m x15^2 /2
9.81 x L x sin36.5 - 3.50L = 112.5
L = 12.05 m
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