At time t = 0, a particle has a charge of 11 muC, is located in the z = 0 plane

Question

At time t = 0, a particle has a charge of 11 muC, is located in the z = 0 plane at x = 0, y = 2. 3 m, and has a velocity equal to 34 m/s i^. Find the magnetic field in the z = 0 plane at the following. X = 1. 2m, y= 3. 4 m x = 2. 3 m, y = 2. 3 m X = 2. 3 m, y = 3. 4 m At time t = 0, a particle has a charge of 11 muC, is located in the z = 0 plane at x = 0, y = 2. 3 m, and has a velocity equal to 34 m/s i^. Find the magnetic field in the z = 0 plane at the following. X = 1. 2m, y= 3. 4 m x = 2. 3 m, y = 2. 3 m X = 2. 3 m, y = 3. 4 m

Explanation / Answer

From Biot-savart law, magnetic field produced by a small current segment,

B = (mue/(4*pi))*(I*dL*sin(theta)/r^2)

we know,

I = dQ/dt

= dQ/dl * dl/dt

I*dl = dq*v

so, magnetic produced by a moving charged particle, B = (mue/(4*pi))*(q*v*sin(theta)/r^2)

a) at x = 1.2 m, y = 3.4 m

sin(theta) = (3.4 - 2.3)/sqrt( 1.1^2 + 1.2^2)

= 0.415

r = sqrt(1.1^2 + 1.2^2)

= 1.628 m

B = (4*pi*10^-7/(4*pi))*(11*10^-6*34*0.415/1.628^2)

= 5.86*10^-12 T

= 5.86 pT

b) x = 2.3 m, y = 2.3, sin(theta) = 0

so, B = 0

c) at x = 2.3 m, y = 3.4 m

sin(theta) = (3.4 - 2.3)/sqrt( 1.1^2 + 2.3^2)

= 0.431

r = sqrt(1.1^2 + 2.3^2)

= 2.55 m

B = (4*pi*10^-7/(4*pi))*(11*10^-6*34*0.431/2.55^2)

= 2.48*10^-12 T

= 2.48 pT

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.